What is factor x^3+13x^2+26x-40 ?

The solution to factor x^3+13x^2+26x-40 is (x-1)(x+4)(x+10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor x^3+13x^2+26x-40

factor

x^{3} + 13 x^{2} + 26 x - 40

(x - 1) (x + 4) (x + 10)

Solution steps

x^{3} + 13 x^{2} + 26 x - 40

Use the rational root theorem

= (x - 1) \frac{x ^{3} + 13 x ^{2} + 26 x - 40}{x - 1}

\frac{x ^{3} + 13 x ^{2} + 26 x - 40}{x - 1} = x^{2} + 14 x + 40

= (x - 1) (x^{2} + 14 x + 40)

Factor

x^{2} + 14 x + 40 : (x + 4) (x + 10)

= (x - 1) (x + 4) (x + 10)

10 0^{\frac{1}{2}} \cdot 2 5^{- 2}

- 3 (w + 2) = 2 (w + 6) + 7

6000 - 25 p = 4000

3 2^{\frac{8}{5}}

x^{2} + 3 x - 40 < 0

What is factor x^3+13x^2+26x-40 ?
The solution to factor x^3+13x^2+26x-40 is (x-1)(x+4)(x+10)