What are the solutions to the equation -v^2+24v+16=-6v^2 ?

The solutions to the equation -v^2+24v+16=-6v^2 are v=-4/5 ,v=-4

Find the zeros of -v^2+24v+16=-6v^2

The zeros of -v^2+24v+16=-6v^2 are v=-4/5 ,v=-4

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- v^{2} + 24 v + 16 = - 6 v^{2}

v = - \frac{4}{5}, v = - 4

Decimal Notation

v = - 0.8, v = - 4

Solution steps

- v^{2} + 24 v + 16 = - 6 v^{2}

Move

6 v^{2}

to the left side

5 v^{2} + 24 v + 16 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 5 \cdot 16}{2 \cdot 5}

2 4^{2} - 4 \cdot 5 \cdot 16 = 16

v_{1, 2} = \frac{- 24 \pm 16}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- 24 + 16}{2 \cdot 5}, v_{2} = \frac{- 24 - 16}{2 \cdot 5}

v = \frac{- 24 + 16}{2 \cdot 5} : - \frac{4}{5}

v = \frac{- 24 - 16}{2 \cdot 5} : - 4

The solutions to the quadratic equation are:

v = - \frac{4}{5}, v = - 4

(x + 7)^{2} = 1

123 - 11 t - 16 t^{2} = 0

\frac{1}{4} + \frac{2}{3}

(\frac{11}{2})^{2}

6 x^{2} - 2 x - 8 = 0

What are the solutions to the equation -v^2+24v+16=-6v^2 ?
The solutions to the equation -v^2+24v+16=-6v^2 are v=-4/5 ,v=-4
Find the zeros of -v^2+24v+16=-6v^2
The zeros of -v^2+24v+16=-6v^2 are v=-4/5 ,v=-4