What are the solutions to the equation 36x^2-48x+16=0 ?

The solutions to the equation 36x^2-48x+16=0 are x= 2/3

Find the zeros of 36x^2-48x+16=0

The zeros of 36x^2-48x+16=0 are x= 2/3

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36 x^{2} - 48 x + 16 = 0

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

36 x^{2} - 48 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 36 \cdot 16}{2 \cdot 36}

(- 48)^{2} - 4 \cdot 36 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 48 ) \pm 0}{2 \cdot 36}

x = \frac{- ( - 48 )}{2 \cdot 36}

\frac{- ( - 48 )}{2 \cdot 36} = \frac{2}{3}

x = \frac{2}{3}

The solution to the quadratic equation is:

x = \frac{2}{3}

\frac{a ^{- 1} + 2}{a ^{- 1} - 2}

\frac{15}{125}

25 (- 8 x^{3} + 3 x^{2} + 6 x)

x^{2} - 6 x = 2

2 y^{2} + 10 y

What are the solutions to the equation 36x^2-48x+16=0 ?
The solutions to the equation 36x^2-48x+16=0 are x= 2/3
Find the zeros of 36x^2-48x+16=0
The zeros of 36x^2-48x+16=0 are x= 2/3