What is factor y^2-4yz+4z^2 ?

The solution to factor y^2-4yz+4z^2 is (y-2z)^2

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factor y^2-4yz+4z^2

factor

y^{2} - 4 yz + 4 z^{2}

(y - 2 z)^{2}

Solution steps

y^{2} - 4 yz + 4 z^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 z^{2} = (2 z)^{2}

- 4 yz = - 2 y \cdot 2 z

= y^{2} - 2 y \cdot 2 z + (2 z)^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

y^{2} - 2 y \cdot 2 z + (2 z)^{2} = (y - 2 z)^{2}

= (y - 2 z)^{2}

3 x^{2} - 5 x = 2

a^{2} + 8 a + 15

6 x^{2} + 39 x - 21

3^{- \frac{1}{2}} \cdot 3 x^{\frac{9}{2}} (3 x)^{- \frac{7}{2}}

- 20 = x - 17