|w|>= 4

Lösung

∣ w ∣ \geq 4

w \leq - 4 or w \geq 4

Intervall-Notation

(- \infty, - 4] \cup [4, \infty)

Schritte zur Lösung

∣ w ∣ \geq 4

Wende Absoluteregel an: Wenn

∣ u ∣ \geq a, a > 0

dann

u \leq - a

u \geq a

w \leq - 4 or w \geq 4

- 2 x^{2} + 8 x + 1 = 0

x^{2} - 11 x = - 28

3 t^{2} = 27

8 v^{2} + v = - 9

2 y + 42 + 2 y = 6