What are the solutions to the equation 2x^2+7x+10=0 ?

The solutions to the equation 2x^2+7x+10=0 are x=-7/4+i(sqrt(31))/4 ,x=-7/4-i(sqrt(31))/4

Find the zeros of 2x^2+7x+10=0

The zeros of 2x^2+7x+10=0 are x=-7/4+i(sqrt(31))/4 ,x=-7/4-i(sqrt(31))/4

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2 x^{2} + 7 x + 10 = 0

x = - \frac{7}{4} + i \frac{31}{4}, x = - \frac{7}{4} - i \frac{31}{4}

Solution steps

2 x^{2} + 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

Simplify

7^{2} - 4 \cdot 2 \cdot 10 : 31 i

x_{1, 2} = \frac{- 7 \pm 31 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 31 i}{2 \cdot 2}, x_{2} = \frac{- 7 - 31 i}{2 \cdot 2}

x = \frac{- 7 + 31 i}{2 \cdot 2} : - \frac{7}{4} + i \frac{31}{4}

x = \frac{- 7 - 31 i}{2 \cdot 2} : - \frac{7}{4} - i \frac{31}{4}

The solutions to the quadratic equation are:

x = - \frac{7}{4} + i \frac{31}{4}, x = - \frac{7}{4} - i \frac{31}{4}

∣ x + 3 ∣ = ∣ 2 x + 1 ∣

1.2 x^{2} + x = 0

\frac{1}{( 2 a - b ) ( a - c )} + \frac{1}{( b - c ) ( b - 2 a )}

9 d + d - 3 d = 14

\frac{5}{8} - \frac{1}{3}

What are the solutions to the equation 2x^2+7x+10=0 ?
The solutions to the equation 2x^2+7x+10=0 are x=-7/4+i(sqrt(31))/4 ,x=-7/4-i(sqrt(31))/4
Find the zeros of 2x^2+7x+10=0
The zeros of 2x^2+7x+10=0 are x=-7/4+i(sqrt(31))/4 ,x=-7/4-i(sqrt(31))/4