What are the solutions to the equation x^2+14x-49=0 ?

The solutions to the equation x^2+14x-49=0 are x=7(sqrt(2)-1),x=-7(1+sqrt(2))

Find the zeros of x^2+14x-49=0

The zeros of x^2+14x-49=0 are x=7(sqrt(2)-1),x=-7(1+sqrt(2))

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x^{2} + 14 x - 49 = 0

x = 7 (2 - 1), x = - 7 (1 + 2)

Solution steps

x^{2} + 14 x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 49 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 49) = 142

x_{1, 2} = \frac{- 14 \pm 14 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 14 2}{2 \cdot 1}, x_{2} = \frac{- 14 - 14 2}{2 \cdot 1}

x = \frac{- 14 + 14 2}{2 \cdot 1} : 7 (2 - 1)

x = \frac{- 14 - 14 2}{2 \cdot 1} : - 7 (1 + 2)

The solutions to the quadratic equation are:

x = 7 (2 - 1), x = - 7 (1 + 2)

- 24

6 x^{2} - 14 = - 5 x - 10

- 8 + 17 x = - x + 28

2 x^{2} + 4 x + 2 = 0

- 3 < \frac{k}{3}

What are the solutions to the equation x^2+14x-49=0 ?
The solutions to the equation x^2+14x-49=0 are x=7(sqrt(2)-1),x=-7(1+sqrt(2))
Find the zeros of x^2+14x-49=0
The zeros of x^2+14x-49=0 are x=7(sqrt(2)-1),x=-7(1+sqrt(2))