What are the solutions to the equation 7x^2-19x-6=0 ?

The solutions to the equation 7x^2-19x-6=0 are x=3,x=-2/7

Find the zeros of 7x^2-19x-6=0

The zeros of 7x^2-19x-6=0 are x=3,x=-2/7

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7 x^{2} - 19 x - 6 = 0

x = 3, x = - \frac{2}{7}

Solution steps

7 x^{2} - 19 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 7 ( - 6 )}{2 \cdot 7}

(- 19)^{2} - 4 \cdot 7 (- 6) = 23

x_{1, 2} = \frac{- ( - 19 ) \pm 23}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 23}{2 \cdot 7}, x_{2} = \frac{- ( - 19 ) - 23}{2 \cdot 7}

x = \frac{- ( - 19 ) + 23}{2 \cdot 7} : 3

x = \frac{- ( - 19 ) - 23}{2 \cdot 7} : - \frac{2}{7}

The solutions to the quadratic equation are:

x = 3, x = - \frac{2}{7}

- 8 v < - 40

\frac{7 i}{7 - 4 i}

∣ 3 x + 2 ∣ > 7

- x^{2} + 1 < 0

\frac{x ^{2}}{1 + x ^{4}} \leq \frac{1}{2}

What are the solutions to the equation 7x^2-19x-6=0 ?
The solutions to the equation 7x^2-19x-6=0 are x=3,x=-2/7
Find the zeros of 7x^2-19x-6=0
The zeros of 7x^2-19x-6=0 are x=3,x=-2/7