What are the solutions to the equation x^2-3x+15=0 ?

The solutions to the equation x^2-3x+15=0 are x= 3/2+i(sqrt(51))/2 ,x= 3/2-i(sqrt(51))/2

Find the zeros of x^2-3x+15=0

The zeros of x^2-3x+15=0 are x= 3/2+i(sqrt(51))/2 ,x= 3/2-i(sqrt(51))/2

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x^{2} - 3 x + 15 = 0

x = \frac{3}{2} + i \frac{51}{2}, x = \frac{3}{2} - i \frac{51}{2}

Solution steps

x^{2} - 3 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 15 : 51 i

x_{1, 2} = \frac{- ( - 3 ) \pm 51 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 51 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 51 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 51 i}{2 \cdot 1} : \frac{3}{2} + i \frac{51}{2}

x = \frac{- ( - 3 ) - 51 i}{2 \cdot 1} : \frac{3}{2} - i \frac{51}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{51}{2}, x = \frac{3}{2} - i \frac{51}{2}

3 x^{2} + 6 x = - 1

\frac{x + 1}{2 - x} > x

4 x^{2} - 7 = 4 x

ln (e) + 1

- 6 w + 1 = - 11

What are the solutions to the equation x^2-3x+15=0 ?
The solutions to the equation x^2-3x+15=0 are x= 3/2+i(sqrt(51))/2 ,x= 3/2-i(sqrt(51))/2
Find the zeros of x^2-3x+15=0
The zeros of x^2-3x+15=0 are x= 3/2+i(sqrt(51))/2 ,x= 3/2-i(sqrt(51))/2