What are the solutions to the equation (x-4)^2=21 ?

The solutions to the equation (x-4)^2=21 are x=sqrt(21)+4,x=-sqrt(21)+4

Find the zeros of (x-4)^2=21

The zeros of (x-4)^2=21 are x=sqrt(21)+4,x=-sqrt(21)+4

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(x - 4)^{2} = 21

x = 21 + 4, x = - 21 + 4

Solution steps

(x - 4)^{2} = 21

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 21 : x = 21 + 4

Solve

x - 4 = - 21 : x = - 21 + 4

The solutions to the quadratic equation are:

x = 21 + 4, x = - 21 + 4

5 + 4

2 x^{3} - 6 x

2 x^{2} + 12 x + 15 = 0

64 x^{2} - 1 = 0

- 4 s \geq - 36

What are the solutions to the equation (x-4)^2=21 ?
The solutions to the equation (x-4)^2=21 are x=sqrt(21)+4,x=-sqrt(21)+4
Find the zeros of (x-4)^2=21
The zeros of (x-4)^2=21 are x=sqrt(21)+4,x=-sqrt(21)+4