Solutions
Solutions to Try Its
1. [latex]\frac{3}{x - 3}-\frac{2}{x - 2}[/latex] 2. [latex]\frac{6}{x - 1}-\frac{5}{{\left(x - 1\right)}^{2}}[/latex] 3. [latex]\frac{3}{x - 1}+\frac{2x - 4}{{x}^{2}+1}[/latex] 4. [latex]\frac{x - 2}{{x}^{2}-2x+3}+\frac{2x+1}{{\left({x}^{2}-2x+3\right)}^{2}}[/latex]Solutions to Odd-Numbered Exercises
1. No, a quotient of polynomials can only be decomposed if the denominator can be factored. For example, [latex]\frac{1}{{x}^{2}+1}[/latex] cannot be decomposed because the denominator cannot be factored. 3. Graph both sides and ensure they are equal. 5. If we choose [latex]x=-1[/latex], then the B-term disappears, letting us immediately know that [latex]A=3[/latex]. We could alternatively plug in [latex]x=-\frac{5}{3}[/latex], giving us a B-value of [latex]-2[/latex]. 7. [latex]\frac{8}{x+3}-\frac{5}{x - 8}[/latex] 9. [latex]\frac{1}{x+5}+\frac{9}{x+2}[/latex] 11. [latex]\frac{3}{5x - 2}+\frac{4}{4x - 1}[/latex] 13. [latex]\frac{5}{2\left(x+3\right)}+\frac{5}{2\left(x - 3\right)}[/latex] 15. [latex]\frac{3}{x+2}+\frac{3}{x - 2}[/latex] 17. [latex]\frac{9}{5\left(x+2\right)}+\frac{11}{5\left(x - 3\right)}[/latex] 19. [latex]\frac{8}{x - 3}-\frac{5}{x - 2}[/latex] 21. [latex]\frac{1}{x - 2}+\frac{2}{{\left(x - 2\right)}^{2}}[/latex] 23. [latex]-\frac{6}{4x+5}+\frac{3}{{\left(4x+5\right)}^{2}}[/latex] 25. [latex]-\frac{1}{x - 7}-\frac{2}{{\left(x - 7\right)}^{2}}[/latex] 27. [latex]\frac{4}{x}-\frac{3}{2\left(x+1\right)}+\frac{7}{2{\left(x+1\right)}^{2}}[/latex] 29. [latex]\frac{4}{x}+\frac{2}{{x}^{2}}-\frac{3}{3x+2}+\frac{7}{2{\left(3x+2\right)}^{2}}[/latex] 31. [latex]\frac{x+1}{{x}^{2}+x+3}+\frac{3}{x+2}[/latex] 33. [latex]\frac{4 - 3x}{{x}^{2}+3x+8}+\frac{1}{x - 1}[/latex] 35. [latex]\frac{2x - 1}{{x}^{2}+6x+1}+\frac{2}{x+3}[/latex] 37. [latex]\frac{1}{{x}^{2}+x+1}+\frac{4}{x - 1}[/latex] 39. [latex]\frac{2}{{x}^{2}-3x+9}+\frac{3}{x+3}[/latex] 41. [latex]-\frac{1}{4{x}^{2}+6x+9}+\frac{1}{2x - 3}[/latex] 43. [latex]\frac{1}{x}+\frac{1}{x+6}-\frac{4x}{{x}^{2}-6x+36}[/latex] 45. [latex]\frac{x+6}{{x}^{2}+1}+\frac{4x+3}{{\left({x}^{2}+1\right)}^{2}}[/latex] 47. [latex]\frac{x+1}{x+2}+\frac{2x+3}{{\left(x+2\right)}^{2}}[/latex] 49. [latex]\frac{1}{{x}^{2}+3x+25}-\frac{3x}{{\left({x}^{2}+3x+25\right)}^{2}}[/latex] 51. [latex]\frac{1}{8x}-\frac{x}{8\left({x}^{2}+4\right)}+\frac{10-x}{2{\left({x}^{2}+4\right)}^{2}}[/latex] 53. [latex]-\frac{16}{x}-\frac{9}{{x}^{2}}+\frac{16}{x - 1}-\frac{7}{{\left(x - 1\right)}^{2}}[/latex] 55. [latex]\frac{1}{x+1}-\frac{2}{{\left(x+1\right)}^{2}}+\frac{5}{{\left(x+1\right)}^{3}}[/latex] 57. [latex]\frac{5}{x - 2}-\frac{3}{10\left(x+2\right)}+\frac{7}{x+8}-\frac{7}{10\left(x - 8\right)}[/latex] 59. [latex]-\frac{5}{4x}-\frac{5}{2\left(x+2\right)}+\frac{11}{2\left(x+4\right)}+\frac{5}{4\left(x+4\right)}[/latex]Licenses & Attributions
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- Precalculus. Provided by: OpenStax Authored by: OpenStax College. Located at: https://cnx.org/contents/[email protected]:1/Preface. License: CC BY: Attribution.
