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Study Guides > Prealgebra

Putting It Together: Integers

At the beginning of this module, we found Rosemary at her birthday party where she was watching her friends try to guess how many jelly beans were in a jar. There is no "correct" way to estimate the number of jelly beans in the jar, rather many different methods that will result in similarly close estimates. We can use some of the concepts from this module to help us make an estimate.

One way to find an estimate for the number of jelly beans is to use multiplication. In the module, we modeled multiplication symbolically, as in this example: To model the product [latex]3\times 8[/latex], we’ll start with a row of [latex]8[/latex] counters. An image of a horizontal row of 8 counters. The other factor is [latex]3[/latex], so we’ll make [latex]3[/latex] rows of [latex]8[/latex] counters. An image of 3 horizontal rows of counters, each row containing 8 counters. Now we can count the result. There are [latex]24[/latex] counters in all. [latex-display]3\times 8=24[/latex-display] We can do a similar thing with the jar of jelly beans, by counting the number of jelly beans along the side of the jar and also along the width of the jar.A glass jar full of different colored jelly beans. There is a line down the side of the jar, as well as a line across the bottom of the jar. Let's estimate that there are 10 jelly beans along the side of the jar and 7 along the bottom of the jar. Multiply: [latex]7\cdot 10=70[/latex]. This tells us that there are 70 jelly beans facing the outside front of the jar.  What about the jelly beans behind them? If we multiply again, we can represent the depth of the jar. We will multiply by 7 again, to represent the depth of the jar. Multiply: [latex]70\cdot 7 = 490[/latex] Does it seem reasonable that the jar will have [latex]490[/latex] jelly beans in it? How would you estimate the number of jelly beans in the jar?

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