The sum of three times a first number and twice a second number is 42. If the second number is subtracted from twice the first number, the result is 14. Find the first number.

Solution

Solution

The number : 10

Solution steps

Represent the numbers with

x and y

number 1 : x

number 2 : y

A.T.Q.:

3 x + 2 y = 42

2 x - y = 14

3 x + 2 y = 42, 2 x - y = 14 : x = 10, y = 6

The number : 10

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