What is the general solution for tan(φ)=1 ?

The general solution for tan(φ)=1 is φ= pi/4+pin

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tan(φ)=1

tan (φ) = 1

φ = \frac{π}{4} + πn

Degrees

φ = 4 5^{\circ} + 18 0^{\circ} n

Solution steps

tan (φ) = 1

General solutions for

tan (φ) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

φ = \frac{π}{4} + πn

φ = \frac{π}{4} + πn

sin (x) = \frac{1}{2}, 0 \leq x \leq 2 π

2 7^{2} = 5 6^{2} + 3 5^{2} - (2 \cdot 56 \cdot 35 \cdot cos (x))

x, sin^{2} (x) - sin (x) - 2 = 0

cos (x - \frac{2 π}{3}) = \frac{1}{2}

3 sin (θ) = 3

What is the general solution for tan(φ)=1 ?
The general solution for tan(φ)=1 is φ= pi/4+pin