What is the general solution for sec(x)-sqrt(2)=0,0<= x<2pi ?

The general solution for sec(x)-sqrt(2)=0,0<= x<2pi is x= pi/4 ,x=(7pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sec(x)-sqrt(2)=0,0<= x<2pi

sec (x) - 2 = 0, 0 \leq x < 2 π

x = \frac{π}{4}, x = \frac{7 π}{4}

Degrees

x = 4 5^{\circ}, x = 31 5^{\circ}

Solution steps

sec (x) - 2 = 0, 0 \leq x < 2 π

Move

2

to the right side

sec (x) - 2 = 0

Add

2

to both sides

sec (x) - 2 + 2 = 0 + 2

Simplify

sec (x) = 2

sec (x) = 2

General solutions for

sec (x) = 2

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x = \frac{π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solutions for the range

0 \leq x < 2 π

x = \frac{π}{4}, x = \frac{7 π}{4}

cos (x) = \frac{15}{19}

cos^{3} (x) = - \frac{1}{2}

(sec (x) + 1)^{2} - tan (x) = 0

cos (A) = \frac{8}{17}

sec (θ) = \frac{6}{- 5}, sec (- θ)

What is the general solution for sec(x)-sqrt(2)=0,0<= x<2pi ?
The general solution for sec(x)-sqrt(2)=0,0<= x<2pi is x= pi/4 ,x=(7pi)/4