What is the general solution for sin(x)tan(x)+sqrt(3)sin(x)=0 ?

The general solution for sin(x)tan(x)+sqrt(3)sin(x)=0 is x=2pin,x=pi+2pin,x=(2pi)/3+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(x)tan(x)+sqrt(3)sin(x)=0

sin (x) tan (x) + 3 sin (x) = 0

x = 2 πn, x = π + 2 πn, x = \frac{2 π}{3} + πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n, x = 12 0^{\circ} + 18 0^{\circ} n

Solution steps

sin (x) tan (x) + 3 sin (x) = 0

Factor

sin (x) tan (x) + 3 sin (x) : sin (x) (tan (x) + 3)

sin (x) tan (x) + 3 sin (x)

Factor out common term

sin (x)

= sin (x) (tan (x) + 3)

sin (x) (tan (x) + 3) = 0

Solving each part separately

sin (x) = 0 or tan (x) + 3 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

tan (x) + 3 = 0 : x = \frac{2 π}{3} + πn

tan (x) + 3 = 0

Move

3

to the right side

tan (x) + 3 = 0

Subtract

3

from both sides

tan (x) + 3 - 3 = 0 - 3

Simplify

tan (x) = - 3

tan (x) = - 3

General solutions for

tan (x) = - 3

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{2 π}{3} + πn

x = \frac{2 π}{3} + πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{2 π}{3} + πn

4 = 5 + 3 sin (2 t - \frac{π}{5})

sin^{2} (2 x) + 2 \cdot cos^{2} (x) - 2 = 0

tan (θ) = - 0.5586, 0 \leq θ < 2 π

6 cos^{2} (x) - sin (x) - 5 = 0, 0 \leq x \leq 2 π

sin (4 x) = sin (3 x)

What is the general solution for sin(x)tan(x)+sqrt(3)sin(x)=0 ?
The general solution for sin(x)tan(x)+sqrt(3)sin(x)=0 is x=2pin,x=pi+2pin,x=(2pi)/3+pin