What is the general solution for tan(θ)=sqrt(3),0<= θ<2pi ?

The general solution for tan(θ)=sqrt(3),0<= θ<2pi is θ= pi/3 ,θ=(4pi)/3

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tan(θ)=sqrt(3),0<= θ<2pi

tan (θ) = 3, 0 \leq θ < 2 π

θ = \frac{π}{3}, θ = \frac{4 π}{3}

Degrees

θ = 6 0^{\circ}, θ = 24 0^{\circ}

Solution steps

tan (θ) = 3, 0 \leq θ < 2 π

General solutions for

tan (θ) = 3

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{π}{3} + πn

θ = \frac{π}{3} + πn

Solutions for the range

0 \leq θ < 2 π

θ = \frac{π}{3}, θ = \frac{4 π}{3}

0 = - cos (8 x) + cos (2 x)

3 cos^{2} (x) + cos (x) - 2 = 0, 0 \leq x \leq 2 π

- 1 = tan^{2} (θ)

y, x = - cos (y)

tan (x) = \frac{3}{6}

What is the general solution for tan(θ)=sqrt(3),0<= θ<2pi ?
The general solution for tan(θ)=sqrt(3),0<= θ<2pi is θ= pi/3 ,θ=(4pi)/3