What is the general solution for cos(b)= 11/14 ?

The general solution for cos(b)= 11/14 is b=0.66694…+2pin,b=2pi-0.66694…+2pin

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cos(b)= 11/14

cos (b) = \frac{11}{14}

b = 0.66694 \dots + 2 πn, b = 2 π - 0.66694 \dots + 2 πn

Degrees

b = 38.21321 \dots^{\circ} + 36 0^{\circ} n, b = 321.78678 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (b) = \frac{11}{14}

Apply trig inverse properties

cos (b) = \frac{11}{14}

General solutions for

cos (b) = \frac{11}{14}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

b = arccos (\frac{11}{14}) + 2 πn, b = 2 π - arccos (\frac{11}{14}) + 2 πn

b = arccos (\frac{11}{14}) + 2 πn, b = 2 π - arccos (\frac{11}{14}) + 2 πn

Show solutions in decimal form

b = 0.66694 \dots + 2 πn, b = 2 π - 0.66694 \dots + 2 πn

sin (x) - cos (x) = - 1, 0 \leq x \leq 2 π

cos (θ) = (\frac{1}{2})

sin^{2} (x) - cos^{2} (x) + sin (x) = 0, 0 \leq x \leq 2 π

cos (θ) = - cos (2 θ)

3 (sin (x) - cos (x)) = 2 (sin (x) + cos (x))

What is the general solution for cos(b)= 11/14 ?
The general solution for cos(b)= 11/14 is b=0.66694…+2pin,b=2pi-0.66694…+2pin