What is the value of -5*sin((2pi)/3) ?

The value of -5*sin((2pi)/3) is -(5sqrt(3))/2

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-5*sin((2pi)/3)

- 5 \cdot sin (\frac{2 π}{3})

- \frac{5 3}{2}

Decimal Notation

- 4.33012 \dots

Solution steps

- 5 sin (\frac{2 π}{3})

Use the following trivial identity:

sin (\frac{2 π}{3}) = \frac{3}{2}

sin (\frac{2 π}{3})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= - 5 \cdot \frac{3}{2}

Simplify

- 5 \cdot \frac{3}{2} : - \frac{5 3}{2}

- 5 \cdot \frac{3}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{3 \cdot 5}{2}

= - \frac{5 3}{2}

(4 + cos (2 \cdot (4 5^{\circ}))) \cdot 1 0^{- 3}

\frac{110 \cdot 2}{π} \cdot (1 + cos (785 4^{\circ}))

arcsin (- \frac{4}{7})

\frac{0.1 cos ( 0.1 ) - sin ( 0.1 )}{0.1 - sin ( 0.1 )}

2 \cdot sin (5 3^{\circ})

What is the value of -5*sin((2pi)/3) ?
The value of -5*sin((2pi)/3) is -(5sqrt(3))/2