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Popular >

ln(1+sin(0))

Solution

ln (1 + sin (0))

Solution

0

Solution steps

ln (1 + sin (0))

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= ln (1 + 0)

Simplify

ln (1 + 0) : 0

ln (1 + 0)

Add the numbers:

1 + 0 = 1

= ln (1)

Apply log rule:

lo g_{a} (1) = 0

= 0

= 0

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Frequently Asked Questions (FAQ)

What is the value of ln(1+sin(0)) ?
The value of ln(1+sin(0)) is 0