What is the value of -6cos(4pi)(1.2) ?

The value of -6cos(4pi)(1.2) is -36/5

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-6cos(4pi)(1.2)

- 6 cos (4 π) (1.2)

- \frac{36}{5}

Decimal Notation

- 7.2

Solution steps

- 6 cos (4 π) (1.2)

= - 6 cos (4 π) \frac{6}{5}

Rewrite using trig identities:

cos (4 π) = 1

cos (4 π)

cos (4 π) = cos (0)

cos (4 π)

Rewrite

4 π

2 π \cdot 2 + 0

= cos (2 π 2 + 0)

Apply the periodicity of

cos

cos (x + 2 π \cdot k) = cos (x)

cos (2 π \cdot 2 + 0) = cos (0)

= cos (0)

= cos (0)

Use the following trivial identity:

cos (0) = 1

cos (0)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

= 1

= - 6 \cdot 1 \cdot \frac{6}{5}

Simplify

- 6 \cdot 1 \cdot \frac{6}{5} : - \frac{36}{5}

- 6 \cdot 1 \cdot \frac{6}{5}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - 1 \cdot \frac{6 \cdot 6}{5}

Multiply the numbers:

6 \cdot 6 = 36

= - 1 \cdot \frac{36}{5}

Multiply:

1 \cdot \frac{36}{5} = \frac{36}{5}

= - \frac{36}{5}

= - \frac{36}{5}

1.5 sin (524 π^{11.33})

(cos (9 0^{\circ})) (cos (3 0^{\circ})) - (sin (9 0^{\circ})) (sin (3 0^{\circ}))

+ cos (0)

8 sin (0.03858) e^{- 0.03858} - 1

arccos (\frac{- 19}{29 \cdot 50})