What is the value of cos^2(-pi)+cos(pi) ?

The value of cos^2(-pi)+cos(pi) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos^2(-pi)+cos(pi)

cos^{2} (- π) + cos (π)

0

Solution steps

cos^{2} (- π) + cos (π)

Use the following property:

cos (- x) = cos (x)

cos (- π) = cos (π)

= cos^{2} (π) + cos (π)

Use the following trivial identity:

cos (π) = (- 1)

cos (π)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= (- 1)

= (- 1)^{2} - 1

Simplify

(- 1)^{2} - 1 : 0

(- 1)^{2} - 1

(- 1)^{2} = 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2}

= 1^{2}

Apply rule

1^{a} = 1

= 1

= 1 - 1

Subtract the numbers:

1 - 1 = 0

= 0

= 0

cos (- 0.6095)

arcsin (117.91633)

8.27 \cdot 9.81 \cdot cos (3 0^{\circ})

\frac{( 100 cos ( 100 ( 0.01 ) ) - \frac{0}{0.1} )}{5}

\frac{( 0.305 )}{sin ( 3.82 )}