What is the value of cot(arccos(-4/5)) ?

The value of cot(arccos(-4/5)) is -4/3

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cot(arccos(-4/5))

cot (arccos (- \frac{4}{5}))

- \frac{4}{3}

Decimal Notation

- 1.33333 \dots

Solution steps

cot (arccos (- \frac{4}{5}))

Rewrite using trig identities:

cot (arccos (- \frac{4}{5})) = \frac{( - \frac{4}{5} )}{1 - ( - \frac{4}{5} ) ^{2}}

Use the following identity:

cot (arccos (x)) = \frac{x}{1 - x ^{2}}

= \frac{( - \frac{4}{5} )}{1 - ( - \frac{4}{5} ) ^{2}}

= \frac{- \frac{4}{5}}{1 - ( - \frac{4}{5} ) ^{2}}

Simplify

= - \frac{4}{3}

arctan (tan (3 0^{\circ}) sin (23.37 5^{\circ}))

(cos (6 0^{\circ})) (sec (6 0^{\circ}))

cos (0) \cdot 7

tan (10 π)

cos^{2} (3 0^{\circ}) + sin^{2} (3 0^{\circ}) - 2 cos (9 0^{\circ})