What is the value of sin(-2 pi/6)+cos(pi/6) ?

The value of sin(-2 pi/6)+cos(pi/6) is 0

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sin(-2 pi/6)+cos(pi/6)

sin (- 2 \frac{π}{6}) + cos (\frac{π}{6})

0

Solution steps

sin (- 2 \cdot \frac{π}{6}) + cos (\frac{π}{6})

Simplify:

- 2 \cdot \frac{π}{6} = - \frac{π}{3}

- 2 \cdot \frac{π}{6}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{π 2}{6}

Cancel the common factor:

2

= - \frac{π}{3}

= sin (- \frac{π}{3}) + cos (\frac{π}{6})

Use the following property:

sin (- x) = - sin (x)

sin (- \frac{π}{3}) = - sin (\frac{π}{3})

= - sin (\frac{π}{3}) + cos (\frac{π}{6})

Use the following trivial identity:

sin (\frac{π}{3}) = \frac{3}{2}

sin (\frac{π}{3})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

Use the following trivial identity:

cos (\frac{π}{6}) = \frac{3}{2}

cos (\frac{π}{6})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{3}{2}

= - \frac{3}{2} + \frac{3}{2}

Simplify

= 0

cos (0.8027)

arccos (\frac{7}{53})

5 sin (1)

arcsin (cot (\frac{π}{2}))

6 sin (2 (\frac{π}{6}))

What is the value of sin(-2 pi/6)+cos(pi/6) ?
The value of sin(-2 pi/6)+cos(pi/6) is 0