What is the value of sin((3pi)/2)+tan(pi)cos(pi/2)-cot((5pi)/6)-sin((7pi)/6) ?

The value of sin((3pi)/2)+tan(pi)cos(pi/2)-cot((5pi)/6)-sin((7pi)/6) is -1/2+sqrt(3)

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sin((3pi)/2)+tan(pi)cos(pi/2)-cot((5pi)/6)-sin((7pi)/6)

Solution

sin (\frac{3 π}{2}) + tan (π) cos (\frac{π}{2}) - cot (\frac{5 π}{6}) - sin (\frac{7 π}{6})

Solution

- \frac{1}{2} + 3

Decimal Notation

1.23205 \dots

Solution steps

sin (\frac{3 π}{2}) + tan (π) cos (\frac{π}{2}) - cot (\frac{5 π}{6}) - sin (\frac{7 π}{6})

tan (π) = tan (0)

tan (π)

Rewrite

π

π + 0

= tan (π + 0)

Apply the periodicity of

tan

tan (x + π) = tan (x)

tan (π + 0) = tan (0)

= tan (0)

= sin (\frac{3 π}{2}) + tan (0) cos (\frac{π}{2}) - cot (\frac{5 π}{6}) - sin (\frac{7 π}{6})

Rewrite as

= sin (\frac{3 π}{2}) - sin (\frac{7 π}{6}) + tan (0) cos (\frac{π}{2}) - cot (\frac{5 π}{6})

Rewrite using trig identities:

sin (\frac{3 π}{2}) - sin (\frac{7 π}{6}) = 2 sin (\frac{π}{6}) cos (\frac{4 π}{3})

sin (\frac{3 π}{2}) - sin (\frac{7 π}{6})

Use the Sum to Product identity:

sin (s) - sin (t) = 2 sin (\frac{s - t}{2}) cos (\frac{s + t}{2})

= 2 sin (\frac{\frac{3 π}{2} - \frac{7 π}{6}}{2}) cos (\frac{\frac{3 π}{2} + \frac{7 π}{6}}{2})

Simplify:

\frac{\frac{3 π}{2} - \frac{7 π}{6}}{2} = \frac{π}{6}

\frac{\frac{3 π}{2} - \frac{7 π}{6}}{2}

Join

\frac{3 π}{2} - \frac{7 π}{6} : \frac{π}{3}

\frac{3 π}{2} - \frac{7 π}{6}

Least Common Multiplier of

2, 6 : 6

2, 6

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Multiply each factor the greatest number of times it occurs in either

2

6

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{3 π}{2} :

multiply the denominator and numerator by

3

\frac{3 π}{2} = \frac{3 π 3}{2 \cdot 3} = \frac{9 π}{6}

= \frac{9 π}{6} - \frac{7 π}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{9 π - 7 π}{6}

Add similar elements:

9 π - 7 π = 2 π

= \frac{2 π}{6}

Cancel the common factor:

2

= \frac{π}{3}

= \frac{\frac{π}{3}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{π}{6}

Simplify:

\frac{\frac{3 π}{2} + \frac{7 π}{6}}{2} = \frac{4 π}{3}

\frac{\frac{3 π}{2} + \frac{7 π}{6}}{2}

Join

\frac{3 π}{2} + \frac{7 π}{6} : \frac{8 π}{3}

\frac{3 π}{2} + \frac{7 π}{6}

Least Common Multiplier of

2, 6 : 6

2, 6

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Multiply each factor the greatest number of times it occurs in either

2

6

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{3 π}{2} :

multiply the denominator and numerator by

3

\frac{3 π}{2} = \frac{3 π 3}{2 \cdot 3} = \frac{9 π}{6}

= \frac{9 π}{6} + \frac{7 π}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{9 π + 7 π}{6}

Add similar elements:

9 π + 7 π = 16 π

= \frac{16 π}{6}

Cancel the common factor:

2

= \frac{8 π}{3}

= \frac{\frac{8 π}{3}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{8 π}{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{8 π}{6}

Cancel the common factor:

2

= \frac{4 π}{3}

= 2 sin (\frac{π}{6}) cos (\frac{4 π}{3})

= 2 sin (\frac{π}{6}) cos (\frac{4 π}{3}) + tan (0) cos (\frac{π}{2}) - cot (\frac{5 π}{6})

Use the following trivial identity:

sin (\frac{π}{6}) = \frac{1}{2}

sin (\frac{π}{6})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

Rewrite using trig identities:

cos (\frac{4 π}{3}) = - \frac{1}{2}

cos (\frac{4 π}{3})

Rewrite using trig identities:

cos (π) cos (\frac{π}{3}) - sin (π) sin (\frac{π}{3})

cos (\frac{4 π}{3})

Write

cos (\frac{4 π}{3})

cos (π + \frac{π}{3})

= cos (π + \frac{π}{3})

Use the Angle Sum identity:

cos (s + t) = cos (s) cos (t) - sin (s) sin (t)

= cos (π) cos (\frac{π}{3}) - sin (π) sin (\frac{π}{3})

= cos (π) cos (\frac{π}{3}) - sin (π) sin (\frac{π}{3})

Use the following trivial identity:

cos (π) = (- 1)

cos (π)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= (- 1)

Use the following trivial identity:

cos (\frac{π}{3}) = \frac{1}{2}

cos (\frac{π}{3})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

Use the following trivial identity:

sin (π) = 0

sin (π)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

Use the following trivial identity:

sin (\frac{π}{3}) = \frac{3}{2}

sin (\frac{π}{3})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= (- 1) \frac{1}{2} - 0 \cdot \frac{3}{2}

Simplify

= - \frac{1}{2}

Use the following trivial identity:

tan (0) = 0

tan (0)

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 0

Use the following trivial identity:

cos (\frac{π}{2}) = 0

cos (\frac{π}{2})

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 0

Use the following trivial identity:

cot (\frac{5 π}{6}) = - 3

cot (\frac{5 π}{6})

cot (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

= - 3

= 2 \cdot \frac{1}{2} (- \frac{1}{2}) + 0 \cdot 0 - (- 3)

Simplify

2 \cdot \frac{1}{2} (- \frac{1}{2}) + 0 \cdot 0 - (- 3) : - \frac{1}{2} + 3

2 \cdot \frac{1}{2} (- \frac{1}{2}) + 0 \cdot 0 - (- 3)

Remove parentheses:

(- a) = - a, - (- a) = a

= - 2 \cdot \frac{1}{2} \cdot \frac{1}{2} + 0 \cdot 0 + 3

2 \cdot \frac{1}{2} \cdot \frac{1}{2} = \frac{1}{2}

2 \cdot \frac{1}{2} \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 \cdot 1 \cdot 2}{2 \cdot 2}

Cancel the common factor:

2

= \frac{1 \cdot 1}{2}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{2}

0 \cdot 0 = 0

0 \cdot 0

Multiply the numbers:

0 \cdot 0 = 0

= 0

= - \frac{1}{2} + 0 + 3

- \frac{1}{2} + 0 + 3 = - \frac{1}{2} + 3

= - \frac{1}{2} + 3

= - \frac{1}{2} + 3

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Frequently Asked Questions (FAQ)

What is the value of sin((3pi)/2)+tan(pi)cos(pi/2)-cot((5pi)/6)-sin((7pi)/6) ?
The value of sin((3pi)/2)+tan(pi)cos(pi/2)-cot((5pi)/6)-sin((7pi)/6) is -1/2+sqrt(3)