What is (-2\times+4)-(\times (-1)) ?

The solution to (-2\times+4)-(\times (-1)) is 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(-2\times+4)-(\times (-1))

(- 2 \cdot + 4) - (\cdot (- 1))

3

Solution steps

(- 2 + 4) - ((- 1))

Follow the PEMDAS order of operations

Calculate within parentheses

(- 2 \cdot + 4) : 4

- 2 + 4

- 2 = n u ll

= 4

= 4 - ((- 1))

Add and subtract (left to right)

4 - ((- 1)) : 3

4 - ((- 1))

Apply rule

- (- a) = + a

- (\cdot (- 1)) = + (- 1)

= 4 + (- 1)

4 + (- 1) = 3

= 3

= 3

2^{3} + 2 - 1

3^{3} - 3^{2} \div 3^{4}

(- 2 - 10)^{2} + (4 - 2 (- 6)^{2})

14 \times + 17 + 16

2 [(- 9) (2^{3}) + (7) (4)]

What is (-2\times+4)-(\times (-1)) ?
The solution to (-2\times+4)-(\times (-1)) is 3