What is (-5)^0+1^5-(-1)^3 ?

The solution to (-5)^0+1^5-(-1)^3 is 3

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(-5)^0+1^5-(-1)^3

(- 5)^{0} + 1^{5} - (- 1)^{3}

3

Solution steps

(- 5)^{0} + 1^{5} - (- 1)^{3}

Follow the PEMDAS order of operations

Calculate exponents

(- 5)^{0} : 1

(- 5)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{0} = 5^{0} = 1

= 1

= 1 + 1^{5} - (- 1)^{3}

Calculate exponents

1^{5} : 1

1^{5}

1^{5} = 1

= 1

= 1 + 1 - (- 1)^{3}

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= 1 + 1 - (- 1)

Add and subtract (left to right)

1 + 1 - (- 1) : 3

1 + 1 - (- 1)

1 + 1 = 2

= 2 - (- 1)

Apply rule

- (- a) = + a

- (- 1) = + 1

= 2 + 1

2 + 1 = 3

= 3

= 3

3 \times (- 9)^{2}

(- 7 \div 1) (- 8 \div 7)

3 - 2 + 5 + 3 + 2 + 7 + 1 - 2

4 (10)^{3}

4 (10)^{2}