What is 10\times (5+3+7)-(6+2)^2 ?

The solution to 10\times (5+3+7)-(6+2)^2 is 86

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10\times (5+3+7)-(6+2)^2

10 \cdot (5 + 3 + 7) - (6 + 2)^{2}

86

Solution steps

10 (5 + 3 + 7) - (6 + 2)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(5 + 3 + 7) : 15

5 + 3 + 7

5 + 3 + 7 = 15

= 15

= 10 \cdot 15 - (6 + 2)^{2}

Calculate within parentheses

(6 + 2) : 8

6 + 2

6 + 2 = 8

= 8

= 10 \cdot 15 - 8^{2}

Calculate exponents

8^{2} : 64

8^{2}

8^{2} = 64

= 64

= 10 \cdot 15 - 64

Multiply and divide (left to right)

10 \cdot 15 : 150

10 \cdot 15

10 \cdot 15 = 150

= 150

= 150 - 64

Add and subtract (left to right)

150 - 64 : 86

150 - 64

150 - 64 = 86

= 86

= 86

(- 2 + 3 - 1) \div (- 3 + 2)

(- 4) - (- 3) + (+ 2) - (+ 1) + (- 8)

(7 + 3 \frac{1}{8}) \div (14 + 6 \frac{1}{4})

- 24 + 36 \div (- 6) \times 2 - 12

(5 - 3)^{3}

What is 10\times (5+3+7)-(6+2)^2 ?
The solution to 10\times (5+3+7)-(6+2)^2 is 86