What is (5(2/5)-3)(2/5+1) ?

The solution to (5(2/5)-3)(2/5+1) is -7/5

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(5(2/5)-3)(2/5+1)

(5 (\frac{2}{5}) - 3) (\frac{2}{5} + 1)

- \frac{7}{5}

Solution steps

(5 (\frac{2}{5}) - 3) (\frac{2}{5} + 1)

Follow the PEMDAS order of operations

Calculate within parentheses

(5 (\frac{2}{5}) - 3) : - 1

5 (\frac{2}{5}) - 3

5 (\frac{2}{5}) - 3 = - 1

5 (\frac{2}{5}) - 3

Remove parentheses:

(a) = a

= 5 \cdot \frac{2}{5} - 3

5 \cdot \frac{2}{5} = 2

5 \cdot \frac{2}{5}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 5}{5}

Cancel the common factor:

5

= 2

= 2 - 3

Subtract the numbers:

2 - 3 = - 1

= - 1

= - 1

= - 1 \cdot (\frac{2}{5} + 1)

Calculate within parentheses

(\frac{2}{5} + 1) : \frac{7}{5}

\frac{2}{5} + 1

\frac{2}{5} + 1 = \frac{7}{5}

\frac{2}{5} + 1

Convert element to fraction:

1 = \frac{1 \cdot 5}{5}

= \frac{1 \cdot 5}{5} + \frac{2}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 5 + 2}{5}

1 \cdot 5 + 2 = 7

1 \cdot 5 + 2

Multiply the numbers:

1 \cdot 5 = 5

= 5 + 2

Add the numbers:

5 + 2 = 7

= 7

= \frac{7}{5}

= \frac{7}{5}

= - 1 \cdot \frac{7}{5}

Multiply and divide (left to right)

- 1 \cdot \frac{7}{5} : - \frac{7}{5}

- 1 \cdot \frac{7}{5}

- 1 \cdot \frac{7}{5} = - \frac{7}{5}

= - \frac{7}{5}

= - \frac{7}{5}

9 + 8 \cdot 8 + 4

6742 - 781 - 89

180 - 45 - 60

2^{0} + 2^{1} + 2^{2}

1 - \frac{1}{4} + \frac{6}{8} - \frac{30}{36}