What is 8\div 2^3-(-7)^2+(-12)^2 ?

The solution to 8\div 2^3-(-7)^2+(-12)^2 is 96

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8\div 2^3-(-7)^2+(-12)^2

8 \div 2^{3} - (- 7)^{2} + (- 12)^{2}

96

Solution steps

8 \div 2^{3} - (- 7)^{2} + (- 12)^{2}

Follow the PEMDAS order of operations

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= 8 \div 8 - (- 7)^{2} + (- 12)^{2}

Calculate exponents

(- 7)^{2} : 49

(- 7)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 7)^{2} = 7^{2} = 49

= 49

= 8 \div 8 - 49 + (- 12)^{2}

Calculate exponents

(- 12)^{2} : 144

(- 12)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 12)^{2} = 1 2^{2} = 144

= 144

= 8 \div 8 - 49 + 144

Multiply and divide (left to right)

8 \div 8 : 1

8 \div 8

8 \div 8 = 1

= 1

= 1 - 49 + 144

Add and subtract (left to right)

1 - 49 + 144 : 96

1 - 49 + 144

1 - 49 = - 48

= - 48 + 144

- 48 + 144 = 96

= 96

= 96

9 + [40 \div (- 8)]

12 - 24 + 12

2 5^{2} + 6 0^{2}

0^{2} + 110 + 18

4 (2)^{2} + 14 (2) - 2

What is 8\div 2^3-(-7)^2+(-12)^2 ?
The solution to 8\div 2^3-(-7)^2+(-12)^2 is 96