The solution to 1/2 (-1)-4 is -9/2

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1/2 (-1)-4

Solution

\frac{1}{2} (- 1) - 4

- \frac{9}{2}

Solution steps

\frac{1}{2} (- 1) - 4

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{1}{2} (- 1) : - \frac{1}{2}

\frac{1}{2} (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{1}{2} (- 1) = - \frac{1}{2} \cdot 1 = - \frac{1}{2}

= - \frac{1}{2}

= - \frac{1}{2} - 4

Add and subtract (left to right)

- \frac{1}{2} - 4 : - \frac{9}{2}

- \frac{1}{2} - 4

- \frac{1}{2} - 4 = - \frac{9}{2}

- \frac{1}{2} - 4

Convert element to fraction:

4 = \frac{4 \cdot 2}{2}

= - \frac{4 \cdot 2}{2} - \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 4 \cdot 2 - 1}{2}

- 4 \cdot 2 - 1 = - 9

- 4 \cdot 2 - 1

Multiply the numbers:

4 \cdot 2 = 8

= - 8 - 1

Subtract the numbers:

- 8 - 1 = - 9

= - 9

= \frac{- 9}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{9}{2}

= - \frac{9}{2}

= - \frac{9}{2}

180 - 63 - 63

- 2^{2} - 4 (2) - 10

- 12 (- 4)^{2}

2^{7} + 5^{2} + 4^{3}

5 \times (- 1) - 4 \times (- 1^{2})