What is the axis (x^2)/7+(y^2)/(16)=1 ?

The axis (x^2)/7+(y^2)/(16)=1 is semi-major axis b=4, semi-minor axis a=sqrt(7)

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axis (x^2)/7+(y^2)/(16)=1

axis

\frac{x ^{2}}{7} + \frac{y ^{2}}{16} = 1

semi - major axis b = 4, semi - minor axis a = 7

Solution steps

\frac{x ^{2}}{7} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{7} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 7 ) ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 7

\frac{( x - 1 ) ^{2}}{a ^{2}} + \frac{( y - 3 ) ^{2}}{b ^{2}} = 1

4 x^{2} - 16 x + 25 y^{2} + 200 y = - 316

3 x^{(2)} + 2 y^{(2)} - 12 x + 8 y + 19 = 0

\frac{( x + 2 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{9} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 4

What is the axis (x^2)/7+(y^2)/(16)=1 ?
The axis (x^2)/7+(y^2)/(16)=1 is semi-major axis b=4, semi-minor axis a=sqrt(7)