What is the axis x^2+y^2-4y=0 ?

The axis x^2+y^2-4y=0 is semi-major axis b=2, semi-minor axis a=2

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axis x^2+y^2-4y=0

axis

x^{2} + y^{2} - 4 y = 0

semi - major axis b = 2, semi - minor axis a = 2

Solution steps

x^{2} + y^{2} - 4 y = 0

Rewrite

x^{2} + y^{2} - 4 y = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 2), a = 2, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 2), b = 2, a = 2

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 6 ) ^{2}}{16} = 1

\frac{x ^{2}}{144} + \frac{y ^{2}}{81} = 1

16 x^{2} - 64 x + 9 y^{2} - 54 y = - 1

\frac{x ^{2}}{16} + \frac{y ^{2}}{7} = 1

4 x^{2} + 9 y^{2} - 64 x + 54 y + 301 = 0

What is the axis x^2+y^2-4y=0 ?
The axis x^2+y^2-4y=0 is semi-major axis b=2, semi-minor axis a=2