What is the center y^2=2(4x-3-x^2) ?

The center y^2=2(4x-3-x^2) is (2,0)

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center y^2=2(4x-3-x^2)

center

y^{2} = 2 (4 x - 3 - x^{2})

(2, 0)

Solution steps

y^{2} = 2 (4 x - 3 - x^{2})

Rewrite

y^{2} - 2 (4 x - 3 - x^{2}) = 0

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 0), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (2, 0), b = 2, a = 1

And the center is:

(2, 0)

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