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Popular >

center x^2+4y^2=4

Solution

center

x^{2} + 4 y^{2} = 4

Solution

(0, 0)

Solution steps

x^{2} + 4 y^{2} = 4

Rewrite

x^{2} + 4 y^{2} = 4

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 1

And the center is:

(0, 0)

Popular Examples

center x^2+4y^2=1 center

x^{2} + 4 y^{2} = 1

center ((x-2)^2}{36}+\frac{(y-6)^2)/4 =1 center

\frac{( x - 2 ) ^{2}}{36} + \frac{( y - 6 ) ^{2}}{4} = 1

center ((x-5)^2}{16}+\frac{(y+3)^2)/4 =1 center

\frac{( x - 5 ) ^{2}}{16} + \frac{( y + 3 ) ^{2}}{4} = 1

center ((x-2)^2}{16}+\frac{(y-1)^2)/9 =1 center

\frac{( x - 2 ) ^{2}}{16} + \frac{( y - 1 ) ^{2}}{9} = 1

center 2x^2+y^2-2x+16y+1=0 center

2 x^{2} + y^{2} - 2 x + 16 y + 1 = 0

Frequently Asked Questions (FAQ)

What is the center x^2+4y^2=4 ?
The center x^2+4y^2=4 is (0,0)