What is the center (x^2)/(64)+(y^2)/(16)=1 ?

The center (x^2)/(64)+(y^2)/(16)=1 is (0,0)

Popular >

center (x^2)/(64)+(y^2)/(16)=1

center

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

(0, 0)

Solution steps

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{64} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{8 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 8, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 8, b = 4

And the center is:

(0, 0)

9 (x - 1)^{2} + 4 y^{2} = 36

9 x^{2} + 25 y^{2} + 18 x + 150 y + 9 = 0

x^{2} + 4 y^{2} - 10 x - 40 y + 121 = 0

x^{2} + 2 y^{2} - 8 y = 0

x^{2} + 36 y^{2} - 16 x - 72 y + 64 = 0

What is the center (x^2)/(64)+(y^2)/(16)=1 ?
The center (x^2)/(64)+(y^2)/(16)=1 is (0,0)