What is the foci (x^2)/8+(y^2)/(24)=1 ?

The foci (x^2)/8+(y^2)/(24)=1 is (0,4),(0,-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (x^2)/8+(y^2)/(24)=1

foci

\frac{x ^{2}}{8} + \frac{y ^{2}}{24} = 1

(0, 4), (0, - 4)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{8} + \frac{y ^{2}}{24} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 26, a = 22

(0, 0 + c), (0, 0 - c)

Compute

c :

c = (26)^{2} - (22)^{2} : 4

(0, 0 + 4), (0, 0 - 4)

Refine

(0, 4), (0, - 4)

\frac{( x - 2 ) ^{2}}{49} + \frac{( y + 1 ) ^{2}}{25} = 1

25 x^{2} + 9 y^{2} + 100 x - 125 = 0

4 x^{2} + 25 y^{2} - 40 x + 150 y + 225 = 0

\frac{( x - 8 ) ^{2}}{64} + \frac{( y - 5 ) ^{2}}{5 ^{2}} = 1

2 x^{2} + 2 y^{2} - 28 x + 12 y + 114 = 0

What is the foci (x^2)/8+(y^2)/(24)=1 ?
The foci (x^2)/8+(y^2)/(24)=1 is (0,4),(0,-4)