What is the foci (x^2)/(484)+(y^2)/(289)=1 ?

The foci (x^2)/(484)+(y^2)/(289)=1 is (sqrt(195),0),(-sqrt(195),0)

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foci (x^2)/(484)+(y^2)/(289)=1

foci

\frac{x ^{2}}{484} + \frac{y ^{2}}{289} = 1

(195, 0), (- 195, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{484} + \frac{y ^{2}}{289} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 22, b = 17

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2 2^{2} - 1 7^{2} : 195

(0 + 195, 0), (0 - 195, 0)

Refine

(195, 0), (- 195, 0)

x^{2} + 9 y^{2} + 2 x - 54 y + 46 = 0

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{9} = 1

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 3 ) ^{2}}{9} = 1

\frac{( x + 3 ) ^{2}}{25} + \frac{( y - 5 ) ^{2}}{169} = 1

\frac{( x - 5 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{25} = 1

What is the foci (x^2)/(484)+(y^2)/(289)=1 ?
The foci (x^2)/(484)+(y^2)/(289)=1 is (sqrt(195),0),(-sqrt(195),0)