What is the foci x^2 1/2+y^2 1/4 =1 ?

The foci x^2 1/2+y^2 1/4 =1 is (0,sqrt(2)),(0,-sqrt(2))

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foci x^2 1/2+y^2 1/4 =1

foci

x^{2} \frac{1}{2} + y^{2} \frac{1}{4} = 1

(0, 2), (0, - 2)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

x^{2} \frac{1}{2} + y^{2} \frac{1}{4} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 2, a = 2

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 2^{2} - 2^{2} : 2

(0, 0 + 2), (0, 0 - 2)

Refine

(0, 2), (0, - 2)

\frac{x ^{2}}{9} + \frac{y ^{2}}{3} = 1

y^{2} = 1 - 25 x^{2}

2 x^{2} - 8 x + 3 y^{2} + 6 y + 5 = 0

36 x^{2} + 288 x + 64 y^{2} - 256 y = 1472

\frac{x ^{2}}{81} + \frac{y ^{2}}{56} = 1

What is the foci x^2 1/2+y^2 1/4 =1 ?
The foci x^2 1/2+y^2 1/4 =1 is (0,sqrt(2)),(0,-sqrt(2))