What is the foci 25(x-1)^2+9(y+4)^2=225 ?

The foci 25(x-1)^2+9(y+4)^2=225 is (1,0),(1,-8)

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foci 25(x-1)^2+9(y+4)^2=225

foci

25 (x - 1)^{2} + 9 (y + 4)^{2} = 225

(1, 0), (1, - 8)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 (x - 1)^{2} + 9 (y + 4)^{2} = 225 :

Ellipse with center

(h, k) = (1, - 4), b = 5, a = 3

(1, - 4 + c), (1, - 4 - c)

Compute

c :

c = 5^{2} - 3^{2} : 4

(1, - 4 + 4), (1, - 4 - 4)

Refine

(1, 0), (1, - 8)

\frac{( x + 1 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{9} = 1

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{49} = 1

\frac{( x - 6 ) ^{2}}{9} + \frac{( y - 9 ) ^{2}}{64} = 1

y^{2} = 16 - x^{2}

\frac{( x - 11 ) ^{2}}{63} + \frac{( y - 13 ) ^{2}}{81} = 1

What is the foci 25(x-1)^2+9(y+4)^2=225 ?
The foci 25(x-1)^2+9(y+4)^2=225 is (1,0),(1,-8)