What is the foci 25x^2+9y^2-54y-144=0 ?

The foci 25x^2+9y^2-54y-144=0 is (0,7),(0,-1)

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foci 25x^2+9y^2-54y-144=0

foci

25 x^{2} + 9 y^{2} - 54 y - 144 = 0

(0, 7), (0, - 1)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

25 x^{2} + 9 y^{2} - 54 y - 144 = 0 :

Ellipse with center

(h, k) = (0, 3), b = 5, a = 3

(0, 3 + c), (0, 3 - c)

Compute

c :

c = 5^{2} - 3^{2} : 4

(0, 3 + 4), (0, 3 - 4)

Refine

(0, 7), (0, - 1)

\frac{( x + 3 ) ^{2}}{49} + \frac{( y - 1 ) ^{2}}{48} = 1

36 x^{2} + 9 y^{2} = 324

\frac{( x + 2 ) ^{2}}{100} + \frac{( y - 5 ) ^{2}}{36} = 1

25 x^{2} + 4 y^{2} - 100 x = 0

\frac{x ^{2}}{7} + \frac{y ^{2}}{43} = 1

What is the foci 25x^2+9y^2-54y-144=0 ?
The foci 25x^2+9y^2-54y-144=0 is (0,7),(0,-1)