What is the foci (x^2)/(64)+(y^2)/(81)=1 ?

The foci (x^2)/(64)+(y^2)/(81)=1 is (0,sqrt(17)),(0,-sqrt(17))

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foci (x^2)/(64)+(y^2)/(81)=1

foci

\frac{x ^{2}}{64} + \frac{y ^{2}}{81} = 1

(0, 17), (0, - 17)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{64} + \frac{y ^{2}}{81} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 9, a = 8

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 9^{2} - 8^{2} : 17

(0, 0 + 17), (0, 0 - 17)

Refine

(0, 17), (0, - 17)

x^{2} + y^{2} - 8 x - 20 y + 115 = 0

9 x^{2} + 16 y^{2} - 18 x - 64 y - 71 = 0

\frac{x ^{2}}{16} + \frac{y ^{2}}{5} = 1

81 x^{2} + 16 y^{2} = 1296

25 x^{2} + 9 y^{2} - 100 x - 90 y + 100 = 0

What is the foci (x^2)/(64)+(y^2)/(81)=1 ?
The foci (x^2)/(64)+(y^2)/(81)=1 is (0,sqrt(17)),(0,-sqrt(17))