What is the foci 9/1 x^2+((9y)/9)^2=9 ?

The foci 9/1 x^2+((9y)/9)^2=9 is (0,2sqrt(2)),(0,-2sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 9/1 x^2+((9y)/9)^2=9

foci

\frac{9}{1} x^{2} + (\frac{9 y}{9})^{2} = 9

(0, 22), (0, - 22)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{9}{1} x^{2} + (\frac{9 y}{9})^{2} = 9 :

Ellipse with center

(h, k) = (0, 0), b = 3, a = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 3^{2} - 1^{2} : 22

(0, 0 + 22), (0, 0 - 22)

Refine

(0, 22), (0, - 22)

4 x^{2} + 16 y^{2} - 4 x - 32 y + 1 = 0

\frac{( x - 1 ) ^{2}}{25} + \frac{( y + 3 ) ^{2}}{5100} = 1

\frac{2 ( x - 6 ) ^{2}}{3} + \frac{7 ( y + 4 ) ^{2}}{4} = 1

(x + 4)^{2} + 9 (y - 3)^{2} = 81

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{9} = 1

What is the foci 9/1 x^2+((9y)/9)^2=9 ?
The foci 9/1 x^2+((9y)/9)^2=9 is (0,2sqrt(2)),(0,-2sqrt(2))