What is the foci (x^2)/(1.5869^2)+(y^2)/(0.9989)=1 ?

The foci (x^2)/(1.5869^2)+(y^2)/(0.9989)=1 is (1.23261…,0),(-1.23261…,0)

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foci (x^2)/(1.5869^2)+(y^2)/(0.9989)=1

foci

\frac{x ^{2}}{1.586 9 ^{2}} + \frac{y ^{2}}{0.9989} = 1

(1.23261 \dots, 0), (- 1.23261 \dots, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{x ^{2}}{1.586 9 ^{2}} + \frac{y ^{2}}{0.9989} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 1.5869, b = 0.9989

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1.586 9^{2} - 0.9989^{2} : 1.23261 \dots

(0 + 1.23261 \dots, 0), (0 - 1.23261 \dots, 0)

Refine

(1.23261 \dots, 0), (- 1.23261 \dots, 0)

\frac{x ^{2}}{36} + \frac{y ^{2}}{49} = 1

\frac{( x + 7 ) ^{2}}{90} + \frac{( y + 8 ) ^{2}}{84} = 1

\frac{( x + 4 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{4} = 1

\frac{x ^{2}}{27} + \frac{y ^{2}}{36} = 1

x^{2} + 4 x + 2 y^{2} + 6 y + 1 = 0

What is the foci (x^2)/(1.5869^2)+(y^2)/(0.9989)=1 ?
The foci (x^2)/(1.5869^2)+(y^2)/(0.9989)=1 is (1.23261…,0),(-1.23261…,0)