What is the foci (x^2)/(16)+(y^2)/(36)=1 ?

The foci (x^2)/(16)+(y^2)/(36)=1 is (0,2sqrt(5)),(0,-2sqrt(5))

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foci (x^2)/(16)+(y^2)/(36)=1

foci

\frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1

(0, 25), (0, - 25)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{16} + \frac{y ^{2}}{36} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 6, a = 4

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 6^{2} - 4^{2} : 25

(0, 0 + 25), (0, 0 - 25)

Refine

(0, 25), (0, - 25)

\frac{( x + 1 ) ^{2}}{28} + \frac{( y + 5 ) ^{2}}{23} = 1

x^{2} - 8 x + 25 y^{2} - 100 y + 91 = 0

\frac{( x + 2 ) ^{2}}{25} + \frac{( y - 4 ) ^{2}}{4} = 1

2 x^{2} + y^{2} = 50

\frac{( x - 5 ) ^{2}}{8 ^{2}} + \frac{( y + 2 ) ^{2}}{1 0 ^{2}} = 1

What is the foci (x^2)/(16)+(y^2)/(36)=1 ?
The foci (x^2)/(16)+(y^2)/(36)=1 is (0,2sqrt(5)),(0,-2sqrt(5))