What is the vertices ((x-4)^2)/(24)+((y-2)^2)/(49)=1 ?

The vertices ((x-4)^2)/(24)+((y-2)^2)/(49)=1 is (4,9),(4,-5)

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vertices ((x-4)^2)/(24)+((y-2)^2)/(49)=1

vertices

\frac{( x - 4 ) ^{2}}{24} + \frac{( y - 2 ) ^{2}}{49} = 1

(4, 9), (4, - 5)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{( x - 4 ) ^{2}}{24} + \frac{( y - 2 ) ^{2}}{49} = 1 :

Ellipse with center

(h, k) = (4, 2), b = 7, a = 26

(4, 2 + 7), (4, 2 - 7)

Refine

(4, 9), (4, - 5)

25 x^{2} + 49 y^{2} = 1225

\frac{2 ( x - 6 ) ^{2}}{3} + \frac{7 ( y + 4 ) ^{2}}{4} = 1 x

\frac{x ^{2}}{12} + \frac{y ^{2}}{144} = \frac{y}{12}

81 x^{2} + 36 y^{2} = 2916

(x)^{2} + \frac{( y - 1 ) ^{2}}{4} = 1

What is the vertices ((x-4)^2)/(24)+((y-2)^2)/(49)=1 ?
The vertices ((x-4)^2)/(24)+((y-2)^2)/(49)=1 is (4,9),(4,-5)