What is the vertices (x^2)/(15)+(y^2)/(16)=1 ?

The vertices (x^2)/(15)+(y^2)/(16)=1 is (0,4),(0,-4)

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vertices (x^2)/(15)+(y^2)/(16)=1

vertices

\frac{x ^{2}}{15} + \frac{y ^{2}}{16} = 1

(0, 4), (0, - 4)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{x ^{2}}{15} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 15

(0, 0 + 4), (0, 0 - 4)

Refine

(0, 4), (0, - 4)

36 x^{2} + 9 y^{2} + 36 y - 288 = 0

36 x^{2} + 16 y^{2} - 64 y - 512 = 0

7 x^{2} + 16 y^{2} = 112

9 x^{2} + 49 y^{2} = 441

16 x^{2} + 9 y^{2} - 96 x + 36 y - 36 = 0

What is the vertices (x^2)/(15)+(y^2)/(16)=1 ?
The vertices (x^2)/(15)+(y^2)/(16)=1 is (0,4),(0,-4)