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Popular >

vertices x^2+y^2=1

Solution

vertices

x^{2} + y^{2} = 1

Solution

(0, 1), (0, - 1)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

x^{2} + y^{2} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 1, a = 1

(0, 0 + 1), (0, 0 - 1)

Refine

(0, 1), (0, - 1)

Popular Examples

vertices x^2+3y^2-4x+12y+13=0 vertices

x^{2} + 3 y^{2} - 4 x + 12 y + 13 = 0

vertices 16x^2+25y^2+64x-200y+64=0 vertices

16 x^{2} + 25 y^{2} + 64 x - 200 y + 64 = 0

vertices 2x^2+y^2=4 vertices

2 x^{2} + y^{2} = 4

vertices 9x^2+4y^2-18x-16y-11=0 vertices

9 x^{2} + 4 y^{2} - 18 x - 16 y - 11 = 0

vertices 4x^2+9y^2=25 vertices

4 x^{2} + 9 y^{2} = 25

Frequently Asked Questions (FAQ)

What is the vertices x^2+y^2=1 ?
The vertices x^2+y^2=1 is (0,1),(0,-1)