What is the vertices 36x^2+9y^2=324 ?

The vertices 36x^2+9y^2=324 is (0,6),(0,-6)

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vertices 36x^2+9y^2=324

vertices

36 x^{2} + 9 y^{2} = 324

(0, 6), (0, - 6)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

36 x^{2} + 9 y^{2} = 324 :

Ellipse with center

(h, k) = (0, 0), b = 6, a = 3

(0, 0 + 6), (0, 0 - 6)

Refine

(0, 6), (0, - 6)

\frac{( x - 6 ) ^{2}}{2} + (y - 2)^{2} = 1

4 x^{2} + y^{2} = 4 x

4 x^{2} + 4 x + y^{2} = 0

\frac{( x ^{2} )}{7} + \frac{( y ^{2} )}{16} = 1

\frac{( x + 1 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{10} = 1

What is the vertices 36x^2+9y^2=324 ?
The vertices 36x^2+9y^2=324 is (0,6),(0,-6)