What is the vertices 9x^2+4y^2+18x-8y-23=0 ?

The vertices 9x^2+4y^2+18x-8y-23=0 is (-1,4),(-1,-2)

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vertices 9x^2+4y^2+18x-8y-23=0

vertices

9 x^{2} + 4 y^{2} + 18 x - 8 y - 23 = 0

(- 1, 4), (- 1, - 2)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

9 x^{2} + 4 y^{2} + 18 x - 8 y - 23 = 0 :

Ellipse with center

(h, k) = (- 1, 1), b = 3, a = 2

(- 1, 1 + 3), (- 1, 1 - 3)

Refine

(- 1, 4), (- 1, - 2)

\frac{( x + 1 ) ^{2}}{16} + \frac{( y + 1 ) ^{2}}{25} = 1

\frac{( x - 4 ) ^{2}}{3} + \frac{y ^{2}}{9} = 1

x^{2} + 64 y^{2} = 64

5 x^{2} + 2 y^{2} = 5

x^{2} + 3 y^{2} + 6 x - 6 y + 9 = 0

What is the vertices 9x^2+4y^2+18x-8y-23=0 ?
The vertices 9x^2+4y^2+18x-8y-23=0 is (-1,4),(-1,-2)